Integrand size = 24, antiderivative size = 363 \[ \int (e x)^{-1+3 n} \left (a+b \text {sech}\left (c+d x^n\right )\right )^2 \, dx=\frac {a^2 (e x)^{3 n}}{3 e n}+\frac {b^2 x^{-n} (e x)^{3 n}}{d e n}+\frac {4 a b x^{-n} (e x)^{3 n} \arctan \left (e^{c+d x^n}\right )}{d e n}-\frac {2 b^2 x^{-2 n} (e x)^{3 n} \log \left (1+e^{2 \left (c+d x^n\right )}\right )}{d^2 e n}-\frac {4 i a b x^{-2 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,-i e^{c+d x^n}\right )}{d^2 e n}+\frac {4 i a b x^{-2 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,i e^{c+d x^n}\right )}{d^2 e n}-\frac {b^2 x^{-3 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,-e^{2 \left (c+d x^n\right )}\right )}{d^3 e n}+\frac {4 i a b x^{-3 n} (e x)^{3 n} \operatorname {PolyLog}\left (3,-i e^{c+d x^n}\right )}{d^3 e n}-\frac {4 i a b x^{-3 n} (e x)^{3 n} \operatorname {PolyLog}\left (3,i e^{c+d x^n}\right )}{d^3 e n}+\frac {b^2 x^{-n} (e x)^{3 n} \tanh \left (c+d x^n\right )}{d e n} \]
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Time = 0.29 (sec) , antiderivative size = 363, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {5548, 5544, 4275, 4265, 2611, 2320, 6724, 4269, 3799, 2221, 2317, 2438} \[ \int (e x)^{-1+3 n} \left (a+b \text {sech}\left (c+d x^n\right )\right )^2 \, dx=\frac {a^2 (e x)^{3 n}}{3 e n}+\frac {4 a b x^{-n} (e x)^{3 n} \arctan \left (e^{c+d x^n}\right )}{d e n}+\frac {4 i a b x^{-3 n} (e x)^{3 n} \operatorname {PolyLog}\left (3,-i e^{d x^n+c}\right )}{d^3 e n}-\frac {4 i a b x^{-3 n} (e x)^{3 n} \operatorname {PolyLog}\left (3,i e^{d x^n+c}\right )}{d^3 e n}-\frac {4 i a b x^{-2 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,-i e^{d x^n+c}\right )}{d^2 e n}+\frac {4 i a b x^{-2 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,i e^{d x^n+c}\right )}{d^2 e n}-\frac {b^2 x^{-3 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,-e^{2 \left (d x^n+c\right )}\right )}{d^3 e n}-\frac {2 b^2 x^{-2 n} (e x)^{3 n} \log \left (e^{2 \left (c+d x^n\right )}+1\right )}{d^2 e n}+\frac {b^2 x^{-n} (e x)^{3 n} \tanh \left (c+d x^n\right )}{d e n}+\frac {b^2 x^{-n} (e x)^{3 n}}{d e n} \]
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Rule 2221
Rule 2317
Rule 2320
Rule 2438
Rule 2611
Rule 3799
Rule 4265
Rule 4269
Rule 4275
Rule 5544
Rule 5548
Rule 6724
Rubi steps \begin{align*} \text {integral}& = \frac {\left (x^{-3 n} (e x)^{3 n}\right ) \int x^{-1+3 n} \left (a+b \text {sech}\left (c+d x^n\right )\right )^2 \, dx}{e} \\ & = \frac {\left (x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int x^2 (a+b \text {sech}(c+d x))^2 \, dx,x,x^n\right )}{e n} \\ & = \frac {\left (x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int \left (a^2 x^2+2 a b x^2 \text {sech}(c+d x)+b^2 x^2 \text {sech}^2(c+d x)\right ) \, dx,x,x^n\right )}{e n} \\ & = \frac {a^2 (e x)^{3 n}}{3 e n}+\frac {\left (2 a b x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int x^2 \text {sech}(c+d x) \, dx,x,x^n\right )}{e n}+\frac {\left (b^2 x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int x^2 \text {sech}^2(c+d x) \, dx,x,x^n\right )}{e n} \\ & = \frac {a^2 (e x)^{3 n}}{3 e n}+\frac {4 a b x^{-n} (e x)^{3 n} \arctan \left (e^{c+d x^n}\right )}{d e n}+\frac {b^2 x^{-n} (e x)^{3 n} \tanh \left (c+d x^n\right )}{d e n}-\frac {\left (4 i a b x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int x \log \left (1-i e^{c+d x}\right ) \, dx,x,x^n\right )}{d e n}+\frac {\left (4 i a b x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int x \log \left (1+i e^{c+d x}\right ) \, dx,x,x^n\right )}{d e n}-\frac {\left (2 b^2 x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int x \tanh (c+d x) \, dx,x,x^n\right )}{d e n} \\ & = \frac {a^2 (e x)^{3 n}}{3 e n}+\frac {b^2 x^{-n} (e x)^{3 n}}{d e n}+\frac {4 a b x^{-n} (e x)^{3 n} \arctan \left (e^{c+d x^n}\right )}{d e n}-\frac {4 i a b x^{-2 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,-i e^{c+d x^n}\right )}{d^2 e n}+\frac {4 i a b x^{-2 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,i e^{c+d x^n}\right )}{d^2 e n}+\frac {b^2 x^{-n} (e x)^{3 n} \tanh \left (c+d x^n\right )}{d e n}+\frac {\left (4 i a b x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int \operatorname {PolyLog}\left (2,-i e^{c+d x}\right ) \, dx,x,x^n\right )}{d^2 e n}-\frac {\left (4 i a b x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int \operatorname {PolyLog}\left (2,i e^{c+d x}\right ) \, dx,x,x^n\right )}{d^2 e n}-\frac {\left (4 b^2 x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int \frac {e^{2 (c+d x)} x}{1+e^{2 (c+d x)}} \, dx,x,x^n\right )}{d e n} \\ & = \frac {a^2 (e x)^{3 n}}{3 e n}+\frac {b^2 x^{-n} (e x)^{3 n}}{d e n}+\frac {4 a b x^{-n} (e x)^{3 n} \arctan \left (e^{c+d x^n}\right )}{d e n}-\frac {2 b^2 x^{-2 n} (e x)^{3 n} \log \left (1+e^{2 \left (c+d x^n\right )}\right )}{d^2 e n}-\frac {4 i a b x^{-2 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,-i e^{c+d x^n}\right )}{d^2 e n}+\frac {4 i a b x^{-2 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,i e^{c+d x^n}\right )}{d^2 e n}+\frac {b^2 x^{-n} (e x)^{3 n} \tanh \left (c+d x^n\right )}{d e n}+\frac {\left (4 i a b x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}(2,-i x)}{x} \, dx,x,e^{c+d x^n}\right )}{d^3 e n}-\frac {\left (4 i a b x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}(2,i x)}{x} \, dx,x,e^{c+d x^n}\right )}{d^3 e n}+\frac {\left (2 b^2 x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int \log \left (1+e^{2 (c+d x)}\right ) \, dx,x,x^n\right )}{d^2 e n} \\ & = \frac {a^2 (e x)^{3 n}}{3 e n}+\frac {b^2 x^{-n} (e x)^{3 n}}{d e n}+\frac {4 a b x^{-n} (e x)^{3 n} \arctan \left (e^{c+d x^n}\right )}{d e n}-\frac {2 b^2 x^{-2 n} (e x)^{3 n} \log \left (1+e^{2 \left (c+d x^n\right )}\right )}{d^2 e n}-\frac {4 i a b x^{-2 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,-i e^{c+d x^n}\right )}{d^2 e n}+\frac {4 i a b x^{-2 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,i e^{c+d x^n}\right )}{d^2 e n}+\frac {4 i a b x^{-3 n} (e x)^{3 n} \operatorname {PolyLog}\left (3,-i e^{c+d x^n}\right )}{d^3 e n}-\frac {4 i a b x^{-3 n} (e x)^{3 n} \operatorname {PolyLog}\left (3,i e^{c+d x^n}\right )}{d^3 e n}+\frac {b^2 x^{-n} (e x)^{3 n} \tanh \left (c+d x^n\right )}{d e n}+\frac {\left (b^2 x^{-3 n} (e x)^{3 n}\right ) \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{2 \left (c+d x^n\right )}\right )}{d^3 e n} \\ & = \frac {a^2 (e x)^{3 n}}{3 e n}+\frac {b^2 x^{-n} (e x)^{3 n}}{d e n}+\frac {4 a b x^{-n} (e x)^{3 n} \arctan \left (e^{c+d x^n}\right )}{d e n}-\frac {2 b^2 x^{-2 n} (e x)^{3 n} \log \left (1+e^{2 \left (c+d x^n\right )}\right )}{d^2 e n}-\frac {4 i a b x^{-2 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,-i e^{c+d x^n}\right )}{d^2 e n}+\frac {4 i a b x^{-2 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,i e^{c+d x^n}\right )}{d^2 e n}-\frac {b^2 x^{-3 n} (e x)^{3 n} \operatorname {PolyLog}\left (2,-e^{2 \left (c+d x^n\right )}\right )}{d^3 e n}+\frac {4 i a b x^{-3 n} (e x)^{3 n} \operatorname {PolyLog}\left (3,-i e^{c+d x^n}\right )}{d^3 e n}-\frac {4 i a b x^{-3 n} (e x)^{3 n} \operatorname {PolyLog}\left (3,i e^{c+d x^n}\right )}{d^3 e n}+\frac {b^2 x^{-n} (e x)^{3 n} \tanh \left (c+d x^n\right )}{d e n} \\ \end{align*}
\[ \int (e x)^{-1+3 n} \left (a+b \text {sech}\left (c+d x^n\right )\right )^2 \, dx=\int (e x)^{-1+3 n} \left (a+b \text {sech}\left (c+d x^n\right )\right )^2 \, dx \]
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\[\int \left (e x \right )^{-1+3 n} {\left (a +b \,\operatorname {sech}\left (c +d \,x^{n}\right )\right )}^{2}d x\]
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Timed out. \[ \int (e x)^{-1+3 n} \left (a+b \text {sech}\left (c+d x^n\right )\right )^2 \, dx=\text {Timed out} \]
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\[ \int (e x)^{-1+3 n} \left (a+b \text {sech}\left (c+d x^n\right )\right )^2 \, dx=\int \left (e x\right )^{3 n - 1} \left (a + b \operatorname {sech}{\left (c + d x^{n} \right )}\right )^{2}\, dx \]
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\[ \int (e x)^{-1+3 n} \left (a+b \text {sech}\left (c+d x^n\right )\right )^2 \, dx=\int { {\left (b \operatorname {sech}\left (d x^{n} + c\right ) + a\right )}^{2} \left (e x\right )^{3 \, n - 1} \,d x } \]
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\[ \int (e x)^{-1+3 n} \left (a+b \text {sech}\left (c+d x^n\right )\right )^2 \, dx=\int { {\left (b \operatorname {sech}\left (d x^{n} + c\right ) + a\right )}^{2} \left (e x\right )^{3 \, n - 1} \,d x } \]
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Timed out. \[ \int (e x)^{-1+3 n} \left (a+b \text {sech}\left (c+d x^n\right )\right )^2 \, dx=\int {\left (a+\frac {b}{\mathrm {cosh}\left (c+d\,x^n\right )}\right )}^2\,{\left (e\,x\right )}^{3\,n-1} \,d x \]
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